(1)工艺品的密度:
ρ=
m
V =
1200g
104cm3 =11.54g/cm3;
(2)设标准工艺品中含金、铜的质量均为m0.若按售货员的说法,则工艺品的密度为
ρ′=
2m0
m0
ρ金 +
m0
ρ铜 =
2ρ金ρ铜
ρ金+ρ铜 =
2×19.3g/cm3×8.9g/cm3
19.3g/cm3+8.9g/cm3 =12.18g/cm3,
则说明售货员的话不可信;
(3)设工艺品中实际含金质量为m1,由ρ=
m
V 可得,
V=
m1
ρ金 +
m?m1
ρ铜 ,
将m=1200g,V=104cm3,ρ金=19.3g/cm3,ρ铜=8.9g/cm3代入上式得
m1=509.2g.
所以这件工艺品的实际含金量为
m1
m =
509.2g
1200g =42.4%.
答:(1)工艺品的密度为11.54g/cm3;
(2)根据售货员的说法计算出的工艺品的密度为12.18g/cm3,说明售货员的话不可信;
(3)这件工艺品的实际含金量为42.4%.